The Hacksmith's original scheme
The most important parts (channel drivers and cap block), have no detail, but a video by Styropyro mentions the name of a component: LM338 (see https://www.ti.com/lit/ds/symlink/lm338.pdf). With the information from its datasheet, I calculated how to get 82V out of it.
- We know that a 0.39 ohm, 5W resistor is used in the channel driver. I have assumed it was R1.
- The datasheet tells us that a constant 1.24V voltage (Vref) is present between the OUT and ADJ pins. From that, I calculated the current passing through R1: 1,24V / 0,39 ohm = 3.18 ampere
- We know that the sum of the voltages on R1 and R2 must be 82V, and the voltage on R1 is 1.24V. This means that the voltage on R2 is 82V - 1.24V = 80.76V
- The value of R2 is 80.76V / 3.18 ampere = 25.40 ohm
Then, a channel driver looks like this:
Channel driver


For the cap block, I have assumed that the four 1000 microfarad, 50V capacitors were connected in parallel. Capacitors, resistors, regulators


The Hacksmith's scheme includes a MOSFET. After reading the specs of several models, I concluded that the correct one is IRF540N (see https://components101.com/irf540n-pinout-equivalent-datasheet)

The last component is explicitly mentioned as LM2596, but its datasheet (see https://www.ti.com/lit/ds/symlink/lm2596.pdf) shows it needs additional components, so I added them in my reverse engineered scheme.

Result of reverse engineering


I still have doubts about it.

1) The video shows that the whole apparatus is powered by 2 LiPo batteries in series, which I identified as https://ttp-technology.it/shop/batterie/190-copy-of-tattu-r-line-v10-6s1p-1050mah-95c-222v-lipo.html But how can channel drivers produce 82V, when they receive 44.4V? The LM338 datasheet never mentions the input voltage in the formulas to calculate the output voltage!

2) Why is there a resistor (of unspecified value) between the two batteries?

3) The video says "ONE of the MOSFETs fused". But the scheme only shows one! How many should there be? Was it an attempt to misdirect the audience?

4) If I connect the LM2596 to the batteries like that... won't it blow up?